Java program take array as input and count element occurrence and then find element with maximum occurrence ?

Previously we have discussed the Program for 
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This is a program to count element occurrence , Here i'am using Scanner to take input from console

and HashMap to store element and his occurrence  in array. We are using HashMap because it store data in form of Keys and Value pair. HashMap<K,V>.

import java.util.ArrayList;

import java.util.Collections;

import java.util.HashMap;

import java.util.List;

import java.util.Map;

import java.util.Map.Entry;

import java.util.Scanner;

public class CountElementOccurence{

 public static void main(String[] args) {

  try {

  Scanner sc=new Scanner(System.in);

  System.out.print("ENTER INPUT ARRAY SIZE : ");

  int inputArraySize = sc.nextInt();

  System.out.println("ENTER "+inputArraySize+" ARRAY ELEMENTS :");

  int[] inputArr=new int[inputArraySize];

  for(int i=0;i<inputArraySize;i++){

  inputArr[i] = sc.nextInt();

  }

  Map<Integer, Integer> map=new HashMap<Integer, Integer>();

  for(int i=0;i<inputArr.length;i++){

   if(map.containsKey(inputArr[i])){

    map.put(inputArr[i], map.get(inputArr[i])+1);

   }

   else{

    map.put(inputArr[i], 1);

   }

  }

  int max = Collections.max(map.values());

  

  List<Integer> keys = new ArrayList<Integer>();

  for(Entry<Integer, Integer> entry : map.entrySet()){

   if(entry.getValue() == max){

    keys.add(entry.getKey());

   }

  }

  System.out.println("OUTPUT\nElement\tCount");

  System.out.println(Collections.min(keys)+"\t"+max);

  } 

  catch (Exception e) {

 System.err.println("** ENTER NUMERIC DIGITS ONLY **");

  }

 }

}

Program Output :-

ENTER INPUT ARRAY SIZE : 3

ENTER 3 ARRAY ELEMENTS :

1

1

5

OUTPUT

Element Count

1         2